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> Find Missing Dates or Numbers within a Range    
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Revision as of 16:29, 26 July 2010
Dallr (Talk | contribs)

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Pacala_ba (Talk | contribs)

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Note: If you have extremely large amounts of records then it might be best to use the inner query and make a table then use that table as the source for the outer query. Note: If you have extremely large amounts of records then it might be best to use the inner query and make a table then use that table as the source for the outer query.
-[code]+[sql]
SELECT T3.YourNumber SELECT T3.YourNumber
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WHERE ((([NextNum]-[YourNumber])>1)); WHERE ((([NextNum]-[YourNumber])>1));
-[/code]+[/sql]
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Note: If you have extremely large amounts of records then it might be best to use the inner query and make a table then use that table as the source for the outer query. Note: If you have extremely large amounts of records then it might be best to use the inner query and make a table then use that table as the source for the outer query.
-[code]+[sql]
SELECT D3.YourDate SELECT D3.YourDate
, D3.NextDate , D3.NextDate
Line 97: Line 97:
WHERE (((DateDiff("d",[YourDate],[NextDate]))>1)); WHERE (((DateDiff("d",[YourDate],[NextDate]))>1));
-[/code]+[/sql]
Date Example 2: Date Example 2:
-[code]+[sql]
SELECT DATEADD("d",1,a.theDate) AS GapStart SELECT DATEADD("d",1,a.theDate) AS GapStart
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WHERE DATEDIFF("d",a.theDate,DATEADD("d",-1,b.theDate))<>0; WHERE DATEDIFF("d",a.theDate,DATEADD("d",-1,b.theDate))<>0;
-[/code]+[/sql]
---- ----

Revision as of 07:52, 1 August 2010

I have also attached a sample application with the code and it can be found here: Media:Find Missing Dates or Numbers within a Range.zip

It shows how to use SQL to identifying missing dates or numbers within a range.


Identifying Missing Numbers The table structure: Table Name : Tbl_Numbers Field name : InvoiceNo

So if your data is like this.

100

101

106

107

109

115


The SQL will return this Missing Data:

102-105

108

110-114


Number Example Code:

To use the code all you need to adjust is the inner query in the FROM Clause with the subquery.

Note: If you have extremely large amounts of records then it might be best to use the inner query and make a table then use that table as the source for the outer query.

SQL


SELECT T3.YourNumber
, T3.NextNum
, IIf([NextNum]-[YourNumber]=2,[YourNumber]+1,[YourNumber]+1 & "-" & [NextNum]-1) AS MissingNumbers
FROM

(SELECT Tbl_Numbers.InvoiceNo AS YourNumber
,(SELECT MIN(InvoiceNo) FROM Tbl_Numbers T1 WHERE T1.InvoiceNo >Tbl_Numbers.InvoiceNo) AS NextNum
FROM Tbl_Numbers) AS T3

WHERE ((([NextNum]-[YourNumber])>1));



Identifying Missing Dates

So if your data is like this.

8/1/09

8/2/09

8/5/09

8/10/09

8/14/09


The SQL will return this Missing Data:

8/3/09 - 8/4/09

8/6/09 - 8/9/09

8/11/09 - 8/13/09

Date Example 1:

To use the code all you need to adjust is the inner query in the FROM Clause with the subquery.

Note: If you have extremely large amounts of records then it might be best to use the inner query and make a table then use that table as the source for the outer query.

SQL

SELECT D3.YourDate
, D3.NextDate
, IIf(DateDiff("d",[YourDate],[NextDate])=2,DateAdd("d",1,[YourDate]),DateAdd("d",1,[YourDate]) & " - " & DateAdd("d",-1,[NextDate])) AS MissingDates
FROM
(SELECT tbl_Dates.TheDate As YourDate
, (SELECT Min(TheDate) FROM Tbl_Dates D1 WHERE D1.TheDate >Tbl_Dates.TheDate) As NextDate
FROM tbl_Dates) AS D3
WHERE (((DateDiff("d",[YourDate],[NextDate]))>1));


Date Example 2:

SQL

SELECT DATEADD("d",1,a.theDate) AS GapStart

, DATEADD("d",-1,b.theDate) AS GapEnd

FROM ( SELECT tbl_Dates.TheDate , (SELECT COUNT(*) FROM Tbl_Dates D1 WHERE D1.TheDate <= tbl_Dates.TheDate) AS ID

FROM tbl_Dates ) AS a

INNER JOIN

( SELECT tbl_Dates.TheDate, (SELECT COUNT(*) FROM Tbl_Dates D1 WHERE D1.TheDate <= tbl_Dates.TheDate) AS ID

FROM tbl_Dates ) AS b

ON a.ID=b.ID-1

WHERE DATEDIFF("d",a.theDate,DATEADD("d",-1,b.theDate))<>0;




--Dallr 08:47, 24 July 2010 (EDT)

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